A 10.00 kg block of ice at -5.00 °C is added to a picnic cooler. How much heat will the ice remove as its melts to water at 0.00 °C?
Added by Brett S.
Step 1
00 °C to 0.00 °C. We can use the specific heat capacity of ice, which is 2.09 J/g·°C: Q1 = m × c × ΔT Q1 = 10.00 kg × 2.09 J/g·°C × (0.00 °C - (-5.00 °C)) Q1 = 1045 J/g × 10.00 kg Q1 = 10450 J So, it takes 10450 J of heat to raise the temperature of the ice to Show more…
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