Question

A 1.05 g iron supplement contains 11.8% Fe by mass. The iron is present in the supplement as C4H2FeO4 (MM = 169.90 g/mol). How many grams of C4H2FeO4 are in the iron supplement?

Name: a 105 g iron supplement contains 118 fe by mass the iron is present in the supplement as c4h2feo4 mm 16990gmol how many grams of c4h2feo4 are in the iron supplement 84752
Uploaded: 2021-11-21T22:44:47-08:00
Duration: 1 min 44 s
Channel: David Collins
Description: a 105 g iron supplement contains 118 fe by mass the iron is present in the supplement as c4h2feo4 mm 16990gmol how many grams of c4h2feo4 are in the iron supplement 84752

          A 1.05 g iron supplement contains 11.8% Fe by mass. The iron is present in the supplement as C4H2FeO4 (MM = 169.90 g/mol). How many grams of C4H2FeO4 are in the iron supplement?

Added by Melody L.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

11/21/2021

Step 1

Given that the iron supplement is 11.8% Fe by mass, we calculate the mass of Fe in the supplement by multiplying the total mass of the supplement by the percentage of Fe. \[ \text{Mass of Fe} = \text{Total mass of supplement} \times \frac{\text{Percentage of Show more…

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A 1.05 g iron supplement contains 11.8% Fe by mass. The iron is present in the supplement as C4H2FeO4 (MM = 169.90 g/mol). How many grams of C4H2FeO4 are in the iron supplement?