00:01
Okay, so here we have a 10 .7 millimeter sample of butane, and it's evaporated in an empty container at a temperature of 30 .5 degrees celsius, and we know the pressure is 900 tor.
00:18
We want to find the volume.
00:20
So because of these different values, we can probably use pv equals nrt.
00:26
And as we're solving for volume, so v equals nrt over p.
00:33
So we know temperature, and we're solving for volume, so v equals nrt over p.
00:37
We know pressure.
00:40
We need to change the units on those, but we don't know moles.
00:45
However, we do have the milliliters of a sample, and we know the density.
00:48
So this can get us in the grams, and then we can go from grams into moles.
00:54
So 10 .7 milliliters of butane, we know that 1 mill is 0 .573 grams.
01:06
And if we look up the molar mass of utane, we see that 1 mole is equal to 58 .1.
01:18
To grams.
01:23
So this will tell us how many moles of butane that we have.
01:27
So 10 .7 times .573 divided by 58 .12 is 1 .055moles.
01:39
So now we know the moles...