a 1.0g bullet is fired into a 0.50 kg block attached to the end of a .60m nonuniform rod of mass 0.50 kg. the block-rod-bullet system then rotates in the plane of the figure
Added by Myles M.
Step 1
First, we need to find the angular velocity of the system after the bullet is fired into the block. To do this, we can use the conservation of angular momentum. The initial angular momentum of the system is given by the product of the bullet's linear momentum and Show more…
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In Fig. 11-53, a $1.0 \mathrm{~g}$ bullet is fired into a $0.50 \mathrm{~kg}$ block attached to the end of a $0.60 \mathrm{~m}$ nonuniform rod of mass $0.50 \mathrm{~kg}$. The block-rod-bullet system then rotates in the plane of the figure, about a fixed axis at $A$. The rotational inertia of the rod alone about that axis at $A$ is $0.060 \mathrm{~kg} \cdot \mathrm{m}^{2}$. Treat the block as a particle. (a) What then is the rotational inertia of the block-rod-bullet system about point $A ?$ (b) If the angular speed of the system about $A$ just after impact is $4.5 \mathrm{rad} / \mathrm{s}$, what is the bullet's speed just before impact?
In Fig. 12-33, a $1.0 \mathrm{~g}$ bullet is fired into a $0.50 \mathrm{~kg}$ block that is mounted on the end of ? $0.60 \mathrm{~m}$ nonuniform rod of mass $0.50 \mathrm{~kg}$. The block-rod-bullet system then rotates about a fixed axis at point $A$. The rotational inertia of the rod alone about $A$ is $0.060$ $\mathrm{kg} \cdot \mathrm{m}^{2}$. Assume the block is small enough to treat as a particle on the end of the rod. (a) What is the rotational inertia of the block-rod-bullet system about point $A ?$ (b) If the rotational speed of the system about $A$ just after the bullet's impact is $4.5$ $\mathrm{rad} / \mathrm{s}$, what is the speed of the bullet just before the impact?
A uniform thin rod of length $0.50 \mathrm{~m}$ and mass $4.0 \mathrm{~kg}$ can rotate in a horizontal plane about a vertical axis through its center. The rod is at rest when a $3.0 \mathrm{~g}$ bullet traveling in the horizontal plane of the rod is fired into one end of the rod. As viewed from above, the direction of the bullet's velocity makes an angle of $60^{\circ}$ with the rod (Fig. $12-30$ ). If the bullet lodges in the rod and the rotational velocity of the rod is $10 \mathrm{rad} / \mathrm{s}$ immediately after the collision, what is the bullet's speed just before impact?
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