A 110.0 g piece of molybdenum metal is heated to $100.0^{\circ} \mathrm{C}$ and placed in a calorimeter that contains 150.0 $\mathrm{g}$ of water at $24.6^{\circ} \mathrm{C} .$ The system reaches equilibrium at a final temperature of $28.0^{\circ} \mathrm{C}$ . Calculate the specific heat of molybdenum metal in $\mathrm{J} /\left(\mathrm{g} \cdot^{\circ} \mathrm{C}\right)$ . The specific heat of water is 4.184 $\mathrm{J} /\left(\mathrm{g} \cdot^{\circ} \mathrm{C}\right)$