00:01
So for part a, we know that the system is in rotational equilibrium.
00:03
So the sum of the torques is going to be equaling zero.
00:07
And this would be for an axis perpendicular to the page, so through the page, and then through the lower end of the boom.
00:16
So we're taking the torque about the lower end.
00:23
So this is equaling zero.
00:24
We can then say that this would be equaling negative 1 .20 kiloons.
00:30
Multiplied by l over 2 times cosine of 65 degrees plus t the tension force multiplied by 3 times the length over 4 minus and then this would be 2 .00 kilonutons multiplied by l cosine of 65 degrees this is again all equaling 0 solving for t and we can see that t is going to be equaling to 1 .47 kiloons.
01:05
This would be our final answer for part a.
01:08
Now, for part b, we simply need to apply newton's second law.
01:12
So the sum of the forces in the x direction, we know to be zero...