Question

a. {(1,(1)/(3)),(2,(1)/(3)),(3,4)} b. {(1,3),(2,4),(2,2)} c. {(1,3),(2,4),(3,1)} With justification, identify which one of the above relations is NOT a function? is a function that is NOT one to one? is a one to one function? Given the following equations a. x^(2)+y^(3)=15 b. x+3y^(2)=17 c. x^(3)-y^(3)=11 With justification, identify which one of the above relations is NOT a function? is a function that is NOT one to one? is a one to one function? A. Let f(x)=(x^(2))/(x+5). Find a simplified formula for (f(a+h)-f(a))/(h) B. Let g(x)=(x^(2)+3x)/(sqrt(x+5)). Find a simplified formula for (g(a-h)-g(a))/(h) Using both interval and set notations, find the domain and range of the following functions: a. f(x)=(sqrt(x+2))/(sqrt(2-x)) b. g(x)=(x)/(-1+sqrt(x+2)) c. h(x)=(1)/(-3+sqrt(-x)) d. e(x)=(1)/(x^(2)+7x+6)+sqrt(-4x+3) Find the domain and range of the graph (both in interval notation and set builder notation) shown below. 1.a.{1,,2,,3,4} b.{1,32,4,2,2} c.{1,3,2,4,3,1} With justification,identify which one of the above relations is NOT a function? is a function that is NOT one to one? is a one to one function 2. Given the following equations a.x2+y3=15 b.x+3y2=17 c.x3-y3=11 With justification,identify which one of the above relations is NOT a function is a function that is NOT one to one is a one to one function? x2 3. A.Letfx= x+5 h B.Letgx= x+5 h 4. Using both interval and set notations,find the domain and range of the following functions: x+2 a.f= 2-x x b.g(x)=-1+x+2 1 c.hx= t-+= 1 5. Find the domain and range of the graph (both in interval notation and set builder notation shown below 

          a. {(1,(1)/(3)),(2,(1)/(3)),(3,4)}
b. {(1,3),(2,4),(2,2)}
c. {(1,3),(2,4),(3,1)}
With justification, identify which one of the above relations
is NOT a function?
is a function that is NOT one to one?
is a one to one function?
Given the following equations
a. x^(2)+y^(3)=15
b. x+3y^(2)=17
c. x^(3)-y^(3)=11
With justification, identify which one of the above relations
is NOT a function?
is a function that is NOT one to one?
is a one to one function?
A. Let f(x)=(x^(2))/(x+5). Find a simplified formula for (f(a+h)-f(a))/(h)
B. Let g(x)=(x^(2)+3x)/(sqrt(x+5)). Find a simplified formula for (g(a-h)-g(a))/(h)
Using both interval and set notations, find the domain and range of the following functions:
a. f(x)=(sqrt(x+2))/(sqrt(2-x))
b. g(x)=(x)/(-1+sqrt(x+2))
c. h(x)=(1)/(-3+sqrt(-x))
d. e(x)=(1)/(x^(2)+7x+6)+sqrt(-4x+3)
Find the domain and range of the graph (both in interval notation and set builder notation) shown below.
1.a.{1,,2,,3,4} b.{1,32,4,2,2} c.{1,3,2,4,3,1} With justification,identify which one of the above relations
is NOT a function? is a function that is NOT one to one?  is a one to one function
2. Given the following equations
a.x2+y3=15 b.x+3y2=17 c.x3-y3=11
With justification,identify which one of the above relations
is NOT a function
is a function that is NOT one to one
is a one to one function?
x2 3. A.Letfx= x+5
h
B.Letgx= x+5
h
4. Using both interval and set notations,find the domain and range of the following functions:
x+2 a.f= 2-x x b.g(x)=-1+x+2 1 c.hx= t-+= 1
5. Find the domain and range of the graph (both in interval notation and set builder notation shown below
Show more…
a 11321334 b 132422 c 132431 with justification identify which one of the above relations is not a function is a function that is not one to one is a one to one function given the following 55325

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a. {(1,(1)/(3)),(2,(1)/(3)),(3,4)} b. {(1,3),(2,4),(2,2)} c. {(1,3),(2,4),(3,1)} With justification, identify which one of the above relations is NOT a function? is a function that is NOT one to one? is a one to one function? Given the following equations a. x^(2)+y^(3)=15 b. x+3y^(2)=17 c. x^(3)-y^(3)=11 With justification, identify which one of the above relations is NOT a function? is a function that is NOT one to one? is a one to one function? A. Let f(x)=(x^(2))/(x+5). Find a simplified formula for (f(a+h)-f(a))/(h) B. Let g(x)=(x^(2)+3x)/(sqrt(x+5)). Find a simplified formula for (g(a-h)-g(a))/(h) Using both interval and set notations, find the domain and range of the following functions: a. f(x)=(sqrt(x+2))/(sqrt(2-x)) b. g(x)=(x)/(-1+sqrt(x+2)) c. h(x)=(1)/(-3+sqrt(-x)) d. e(x)=(1)/(x^(2)+7x+6)+sqrt(-4x+3) Find the domain and range of the graph (both in interval notation and set builder notation) shown below. 1.a.{1,,2,,3,4} b.{1,32,4,2,2} c.{1,3,2,4,3,1} With justification,identify which one of the above relations is NOT a function? is a function that is NOT one to one? is a one to one function 2. Given the following equations a.x2+y3=15 b.x+3y2=17 c.x3-y3=11 With justification,identify which one of the above relations is NOT a function is a function that is NOT one to one is a one to one function? x2 3. A.Letfx= x+5 h B.Letgx= x+5 h 4. Using both interval and set notations,find the domain and range of the following functions: x+2 a.f= 2-x x b.g(x)=-1+x+2 1 c.hx= t-+= 1 5. Find the domain and range of the graph (both in interval notation and set builder notation shown below
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Transcript

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00:01 Okay, so your domain is your x values.
00:05 And as you can see that as you go up, your values are slowly extending outward.
00:15 So your domain is negative infinity to infinity.
00:19 Because of that, i can stop at the rest of them because none of the other ones have a domain from negative infinity to infinity.
00:25 But the range is your y values.
00:27 So my y values start right here at 1.
00:30 Two, three, four.
00:32 So they start at negative four and they go to infinity.
00:36 And it's a bracket because it's actually equal to it.
00:39 So that's why that's the range.
00:42 So the next one would, what would not be in the domain? so which one of these would make square root x plus four less than zero? so if i plug in zero, so zero plus four is four and i can do the square root of four, so that's fine.
01:03 So, zero is right.
01:05 Five plus four gives me square root in nine.
01:09 That works.
01:11 Negative three, so negative three plus four gives me a positive one.
01:16 So square root of one, that one works.
01:18 It's one.
01:18 All right.
01:19 Now, negative eight, negative eight plus four gives me the square root of negative four, which is imaginary, and that is not part of my graph.
01:29 So this would make would not be in the domain.
01:34 Which of the following would not be part of the domain.
01:37 So we need to know which one for your denominator, x plus three, cannot equal zero.
01:44 So x cannot be equal to negative three.
01:48 So negative three is your excluded value...
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