00:01
Here is the solution.
00:04
Here given that a truck and a car where the mass of the car is given which is 1 -230 kilogram and mass of the truck is 2180 kilogram.
00:20
And here given that the car push horizontally against the ground with the force of 2420 newton and a frictional force between the truck and the wheels.
00:29
That means the rolling friction of the truck is 750 newton.
00:32
So here we have to find out the value of acceleration and what is the magnitude of the force that cars applies to the truck.
00:39
So here we have to find out the value of a and the value of force on truck due to car.
00:45
So here the force exert by the car is 2420.
00:51
Or here we can say that the ground exert a force which is 2420 newton and this force is move car as well as truck also so if we are talking about the free body diagram of the whole system it will be like this it is the fc and that is the frictional force f r and both truck and car move with the same acceleration which is a so from this equation or from this free body diagram we can write it as that fc minus frictional force is equals to the total mass of the system multiply by acceleration so here acceleration of the system is equals to to fc minus fr divided by the total mass.
01:31
And here fc, which is equals to 440 minus fr 750 divided by the mass of truck plus mass of car.
01:41
Here is the total mass, right? here is the total mass and total mass is mass of car plus mass of truck which is equals to 1230 plus 2180.
01:51
So now here the value of acceleration is equals to 1 .08 meter per second is square.
01:57
This is the acceleration for both the truck and the car because both are moving with the same acceleration...