A 1250-kg compact car is moving with velocity v⃗ 1=36.2i^+12.7j^m/s. It skids on a frictionless icy patch and collides with a 448-kg hay wagon moving with velocity v⃗ 2=13.8i^+10.2j^m/s.
Added by Kaden W.
Step 1
Momentum is the product of mass and velocity. So, the initial momentum of the car is (1250 kg)(36.2i^ + 12.7j^ m/s) and the initial momentum of the hay wagon is (448 kg)(13.8i^ + 10.2j^ m/s). Show more…
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A $1250-\mathrm{kg}$ car is moving with velocity $\vec{v}_{1}=36.2 \hat{\imath}+12.7 \hat{\jmath} \mathrm{m} / \mathrm{s}$ It skids on a frictionless icy patch and collides with a $448-\mathrm{kg}$ hay wagon with velocity $\vec{v}_{2}=13.8 \hat{\imath}+10.2 \hat{\jmath} \mathrm{m} / \mathrm{s} .$ If the two stay together, what's their velocity?
A $2250 \mathrm{kg}$ car traveling at $10.0 \mathrm{m} / \mathrm{s}$ collides with a $2750 \mathrm{kg}$ car that is initially at rest at a stoplight. The cars stick together and move $2.50 \mathrm{m}$ before friction causes them to stop. Determine the coefficient of kinetic friction between the cars and the road, assuming that the negative acceleration is constant and that all wheels on both cars lock at the time of impact.
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