A 12.6 V battery is connected in series with a resistor and an inductor. The circuit has a time constant of 492 µs, and the maximum current is 196 mA. What is the value of the inductance? mH
Added by David C.
Step 1
We know that τ = 492 µs and the battery voltage is 12.6 V. We also know that the maximum current is 196 mA, which means that the resistance must be: R = V/I = 12.6 V / 0.196 A = 64.3 ohms Now we can rearrange the formula for τ to solve for L: L = Rτ L = 64.3 Show more…
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