00:01
We have to find the final temperature of a piece of tin that was placed in ethanol.
00:05
And we're going to set the q for the tin, the amount of heat the tin has, equal to the negative value of the q of the ethanol.
00:14
And we're going to use q equals mcat.
00:18
So we're going to have q is equal to mc delta t, for the tin is going to equal the mc delta t, which is equal to the negative q of the ethanol.
00:36
Because we're going to have negative q on the ethanol side, we're going to have to multiply our entire mcat equation by negative one.
00:46
So all we have to do now is remember that delta t for both sides is going to be t final.
00:54
The value that we're looking for minus t initial, the values we were given.
01:01
So on the tin side, we have the mass 10 .69 times the c value 0 .213, times the initial temperature, we have t final minus 12 .44.
01:21
And this is going to equal the q for the ethanol.
01:25
I'm running out of room, so i'm just going to move it down a little bit.
01:29
That's going to be 24 .54 times 2 .44 times, again we're looking for tf, and that's going to be 68 .61 for the initial temperature, and all of that times negative one.
01:50
So let's simplify this down.
01:52
We have 10 .69 times 0 .213, and that's going to be 2 .27697 times tf minus 12 .44...