Question

A 13.0 g wire of length L = 62.0 cm is suspended by a pair of flexible leads in a uniform magnetic field of magnitude 0.440 T (see figure at at right). What are the (a) magnitude and (b) direction (left or right) of the current required to remove the tension in the supporting leads? Assume the leads do not act as a spring pulling the wire upwards. Acceleration due to gravity is 9.8 m s?¹.

          A 13.0 g wire of length L = 62.0 cm is suspended by a pair of flexible leads in a uniform magnetic field of magnitude 0.440 T (see figure at at right).

What are the (a) magnitude and (b) direction (left or right) of the current required to remove the tension in the supporting leads?

Assume the leads do not act as a spring pulling the wire upwards. Acceleration due to gravity is 9.8 m s?¹.

A 13.0 g wire of length L = 62.0 cm is suspended by a pair of flexible leads in a uniform magnetic field of magnitude 0.440 T (see figure at at right).

What are the (a) magnitude and (b) direction (left or right) of the current required to remove the tension in the supporting leads?

Assume the leads do not act as a spring pulling the wire upwards. Acceleration due to gravity is 9.8 m s?¹.

Added by Jennifer A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

05/25/2022

Step 1

Given: Mass of wire, m = 13.0 g = 13.0 x 10^-3 kg Show more…

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A 13.0 g wire of length L = 62.0 cm is suspended by a pair of flexible leads in a uniform magnetic field of magnitude 0.440 T (see figure at at right). What are the (a) magnitude and (b) direction (left or right) of the current required to remove the tension in the supporting leads? Assume the leads do not act as a spring pulling the wire upwards. Acceleration due to gravity is 9.8 m s⁻¹.