00:01
If we neglect external forces, then momentum must be conserved.
00:04
That means the total momentum of the objects before and after they collide must be equal to each other.
00:09
This problem is given when a 15 -gram bullet that is fired at a speed of 50 meters per second would hit a 3 -kilogram block that sits at the edge of a 75 -centimeter high table.
00:21
The bullet invents itself in the block as a result in the two move as one.
00:25
We want to find the distance that the block moves.
00:30
Directly below the table sketch where the block lands.
00:35
So we want to find the deed in this given illustration.
00:39
So first is that we will find the velocity by which the block embedded with a bullet move as it launches or that means the velocity on the horizontal velocity that the block bullet system launches itself from the table.
00:56
So for that we will use the conservation of the momentum let's say the momentum before so that's the sum of the momentum of the bullet and the block so the momentum before collision must be equal to the momentum after the collision now since the bullet and the block would move as one so we would have it as mb plus n mb here and p is the speed by which the two move and that's the speed horizontal speed by which the bullet block system them notches itself from the edge of the table.
01:37
Now the mass of the bullet is 15 grams.
01:42
Its speed prior to hitting the block is 650...