A 1.5 Kg object oscillates with simple harmonic motion of a spring of force constant K = 500 N/m. Its maximum velocity is 70 cm/s. What is the total energy? What is the amplitude of the oscillation?
Added by Carolina S.
Step 1
ω = √(500 N/m / 1.5 kg) = √(1000/3) s^(-1) Now, we can find the amplitude (A) using the formula: A = v_max / ω where v_max is the maximum velocity. A = (70 cm/s) / (√(1000/3) s^(-1)) = 0.07 m / (√(1000/3) s^(-1)) Show more…
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