A 1.50-kg block is pushed against a spring with negligible mass and force constant k = 350 N/m, compressing it 22cm. When the block is released, it moves along a frictionless, horizontal surface and then up a frictionless incline with slope 30.0∘
Added by William C.
Step 1
The potential energy stored in a spring is given by the formula: PE = 0.5 * k * x^2 where PE is the potential energy, k is the force constant (350 N/m), and x is the compression distance (22 cm = 0.22 m). Plugging in the values, we get: PE = 0.5 * 350 * Show more…
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