A 1.50 V battery supplies 0.323 W of power to a small flashlight for 26.7 min. (a) How much charge does it move? C (b) How many electrons must move to carry this charge?
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Given power P = 0.323 W and voltage V = 1.50 V. So, I = P / V = 0.323 / 1.50 = 0.215 A. Show more…
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