A 1500-nF capacitor with circular parallel plates 2.0 cm in diameter is accumulating charge at the rate of 39.0 mC/s at some instant in time. What will be the induced magnetic field strength 10.5 cm radially outward from the center of the plates?
Added by Mary G.
Step 1
The rate of charge accumulation is given as 39.0 mC/s, which is equivalent to 0.039 C/s. Therefore, the current I is: \[ I = 0.039 \, \text{A} \] Show more…
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(II) A $1500-n F$ capacitor with circular parallel plates $2.0 \mathrm{~cm}$ in diameter is accumulating charge at the rate of $38.0 \mathrm{mC} / \mathrm{s}$ at some instant in time. What will be the induced magnetic field strength $10.0 \mathrm{~cm}$ radially outward from the center of the plates? What will be the value of the field strength after the capacitor is fully charged?
(II) A 1200 -nF capacitor with circular parallel plates 2.0 $\mathrm{cm}$ in diameter is accumulating charge at the rate of 35.0 $\mathrm{mC} / \mathrm{s}$ at some instant in time. What will be the magnitude of the induced magnetic field 10.0 $\mathrm{cm}$ radially outward from the center of the plates? What will be the magnitude of the field after the capacitor is fully charged?
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