Question

A 18-g projectile is shot vertically upward by a spring-loaded toy gun. The spring of the toy gun compresses by 4.2 cm and has a spring constant of $k = 16 \text{ N/cm}$. How high from the spring's equilibrium position can the projectile reach? Give your answer in units of m. You may assume the spring is massless and ideal, ignore effects due to friction, and assume that $|g| = 9.81 \text{ m/s}^2$.

          A 18-g projectile is shot vertically upward by a spring-loaded toy gun. The spring of the toy gun compresses by 4.2 cm and has a spring constant of $k = 16 \text{ N/cm}$. How high from the spring's equilibrium position can the projectile reach?
Give your answer in units of m. You may assume the spring is massless and ideal, ignore effects due to friction, and assume that $|g| = 9.81 \text{ m/s}^2$.

A 18-g projectile is shot vertically upward by a spring-loaded toy gun. The spring of the toy gun compresses by 4.2 cm and has a spring constant of k = 16 N/cm. How high from the spring's equilibrium position can the projectile reach?
Give your answer in units of m. You may assume the spring is massless and ideal, ignore effects due to friction, and assume that |g| = 9.81 m/s^2.

Added by Gregory G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

09/12/2022

Step 1

The potential energy stored in a spring is given by the formula: PE = 0.5 * k * x^2 where: PE = potential energy stored in the spring k = spring constant (16 N/cm = 16 N / 0.01 m = 1600 N/m) x = compression distance (4.2 cm = 0.042 m) Plugging in the values: PE Show more…

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A 18-g projectile is shot vertically upward by a spring-loaded toy gun. The spring of the toy gun compresses by 4.2 cm and has a spring constant of k = 16 N/cm. How high from the spring's equilibrium position can the projectile reach? Give your answer in units of m. You may assume the spring is massless and ideal, ignore effects due to friction, and assume that |g| = 9.81 m/s^2.