00:01
Hi, in this question we have first let us find the value of w0.
00:04
So, for one phase transformer so we have w0 is given by it is v1 into i0 cos phi.
00:15
So, here cos phi is unknown.
00:18
So, we have cos phi 0 is equal to it is w is 650 divided by 220 into 9 .5.
00:25
So, this is equal to 0 .311 therefore sin phi 0 will be equal to so 2.
00:32
So, sin phi 0 is equal to 0 .95 ampere.
00:36
So, 0 .95 then we have to find the reactive current and active current.
00:42
So, reactive current is so active current is iv which is i0 into cos phi that is equal to so 9 .5 into 0 .311.
00:51
So, which is 2 .95 ampere then we have the reactive current is equal to i0 into sin phi that is 9 .5 into 0 .95 that is equal to 9 .02 ampere.
01:05
We have the resistance is equal to v1 by iv which is equal to 220 divided by 2 .95 that is 74 .47 ohm and we have the reactance is equal to it is v1 divided by iu which is equal to 220 divided by 9 .02 which is 24 .36 ohm.
01:28
Then from this test we have the impedance value is given by it is v divided by i2...