Question

A 2-kg block B is released from rest by a spring that is initially compressed by 0.2 m. It then slides on the floor (μk = 0.2) and got hit by a 1-kg ball as shown. Determine the velocity of the block after collision. The coefficient of restitution is e = 0.8. Neglect the rolling friction on the ball.

Name: a 2 kg block b is released from rest by a spring that is initially compressed by 02 m it then slides on the floor k 02 and got hit by a 1 kg ball as shown determine the velocity of the block 22714
Uploaded: 2024-06-22T16:54:21-08:00
Duration: 2 min 3 s
Channel: Adi S
Description: a 2 kg block b is released from rest by a spring that is initially compressed by 02 m it then slides on the floor k 02 and got hit by a 1 kg ball as shown determine the velocity of the block 22714

          A 2-kg block B is released from rest by a spring that is initially compressed by 0.2 m. It then slides on the floor (μk = 0.2) and got hit by a 1-kg ball as shown. Determine the velocity of the block after collision. The coefficient of restitution is e = 0.8. Neglect the rolling friction on the ball.

Added by Veronica B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

06/22/2024

Step 1

The spring force can be calculated using Hooke's law, F = kx, where k is the spring constant and x is the displacement (0.2 m in this case). However, we don't know the spring constant. But we can use the principle of conservation of energy. The potential energy Show more…

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A 2-kg block B is released from rest by a spring that is initially compressed by 0.2 m. It then slides on the floor (μk = 0.2) and got hit by a 1-kg ball as shown. Determine the velocity of the block after collision. The coefficient of restitution is e = 0.8. Neglect the rolling friction on the ball.