00:01
Hello everyone in this problem we have given density is equal to 7850 kg per meter cube.
00:08
Also we have given the diagram in this manner so i'm just considering it is a first portion this one is second portion and this one is a third portion.
00:20
So first of all i will calculate the masses across the each section.
00:27
So for the first section that is m1 is equals to row of v1.
00:32
Where v1 is a volume so it comes 580 into volume that is 0 .002 into 0 .30 square for the first portion this is a total distance that is 150 plus 150 that is 300 so it comes out 1 .413 kg in the similar way for the second section that is m2 is given as row of v2 which comes out 7850 into 0 .002 into 0 .10 into 0 .120.
01:19
So after multiplying we get 0 .2826 kg and for the third section that is m3 can be written as which have same dimension so it comes out as m2 which is 0 .2826 and after that in the first part of the problem we are calculating the moment of inertia along the x -axis firstly we will calculate the moment of inertia of first section then second section then third section and after that we will add all the terms so the moment of inertia for x -axis for the first section comes out 1 by 12 into 1 .1.
02:12
413 which is a mass into r square that is 0 .30 square which is equals to 1 .06 into 10 to par minus 2 kg per meter square in the similar way the i of x for second section comes out i of x dash plus m into d square so it can be written as 1 by 12 into 0 .2826 into 0 .120 square plus 0 .2826 into distance that is 0 .15 square plus 0 .0 square.
03:04
So after multiplying we get 7 .71 into 10 raised to par minus 3 kg meter square.
03:14
In the similar way that is movement of inertia along x -axis for third section which is equals to movement of inertia 4 second which comes out 7 .71 into 10 to power minus 3 kg meter square so the total movement of inertia along x -axis can be written as the summation of all three terms that is 1 .06 10 to per minus 2 plus 7 .71 into 10 days to par minus 3 plus 7 .71 into 10 10 days to power minus 3.
03:48
So after adding we get 2 .6 into 10 to power minus 2 kg per meter square.
03:57
In the similar way we will calculate along y -axis.
04:07
So movement of inertia along y -axis for the first section comes out 1 by 12 into 1 .413 into distance that is 0 .30 square plus 0 .30 square.
04:22
After multiplying, it comes out 2 .12 into 10 raise to par minus 2 kg meter square...