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Hi, in this question we are given that xcel reacts with k -o -h to form kcl and water.
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Concentration of xl is 0 .115 molars and for k -o -h 0 .1014 mollards.
00:23
Firstly, we will determine number of moles of xcel which is equal to molarity, multiply by its.
00:36
Volume.
00:38
So from here number of moles comes out 2 .3 .0 millimoles.
00:53
We need to determine the ph of h .c .l is a strong acid.
00:59
Therefore it will dissociates into h -positive and cl negative.
01:08
Concentration of h -positive ion will be equal to that of xl -115 molar and ph is determined by taking minus log of the concentration of h positive.
01:26
So ph comes out 0 .94.
01:38
Now in the next part we will determine number of millimoles of k -o -h added will be equal to its molarity and its volume.
02:00
Therefore number of moles comes out 1 .521 mili moles as one mole of xl reacts with one mole of kohh therefore remaining moles of xcel will be equal to millimoles of xcel minus millimoles of kohh which comes out 0 .779 millimoles.
02:36
The total volume will be equal to the volume of k -o -h and volume of xcel, that is 35 milliliters.
02:48
Now we will determine the final concentration of x -l with the total volume.
02:57
Dividing the remaining moles with the volume we get 0 .022 molards...