00:01
In this problem, we have given a setup of two lenses which are placed 30 cm apart from each other.
00:16
This is 30 cm and here this is the object.
00:23
If we draw a rough ray diagram, we can see that it will form something like that an image.
00:34
This image will act, this is the lens 1 and this is the lens 2.
00:39
This image will act as the object for the lens 2.
00:46
So this will something look like that and if we extend it behind, it will look something like that.
00:55
And when we now draw one more line that passes through the center of pole, it will cut it here.
01:07
So, this will be an image formed by the second lens.
01:11
This is image.
01:14
So we have given some data that is height of object 2 cm, distance of object from the first lens is 22 cm, focal length of the first lens is 11 cm and focal length of second is 12 cm.
01:39
So now let us use the lens maker formula to solve this problem.
01:56
The lens maker formula is 1 upon f equal 1 upon v minus 1 upon u.
02:03
Here f is the focal length, v is the distance of image, u is the distance of object.
02:12
So now let us put this formula for the lens 1.
02:20
1 upon f1 equal 1 upon v1 minus 1 upon u1.
02:28
V1 is the image formed for the lens 1.
02:33
So let us simply put the values in this formula.
02:37
1 upon 11, 1 upon v1 minus 1 upon u that is 22 cm...