A 2200 kg satellite used in a cellular telephone network is in a circular orbit at a height of 750 km above the surface of the earth.
What is the gravitational force on the satellite?
F = 16.7 * 10^3 N
Review your calculations and make sure you round to 3 significant figures in the last step
No credit lost. Try again.
Part B
What fraction is this force of the satellite's weight at the surface of the earth?
.773 %
Previous Answers Request Answer
Incorrect; Try Again; 5 attempts remaining