A 230 v shunt motor has a nominal armature current of 60 a...

A 230 V shunt motor has a nominal armature current of 60 A. If the armature resistance is 0.15 ohm, calculate the following: a. The counter-emf [V]. b. The power supplied to the armature [W]. c. The mechanical power developed by the motor [kW] and [hp]. d. The initial starting current if the motor is directly connected across the 230 V line, and the value of the starting resistor needed to limit the initial current to 115 A.

Transcript

00:01 In this question here we have given a voltage that is vt equals to 230 volt and armature current that is ia is equals to 60 ampere and armature registrant that is ra equals to 0 .15 om so here let's see a part so here we have to find the back emf so here the formula for this is eb equals to vt minus i a r a so here substitute the values eb equals to vt is 230 minus i a is 60 multiply by 0 .15 so here when we calculate it we get i b equals to vt 221 volt so here this is our answer for a part now let's see b part so here we have to find the power supplied power supplied to the armature that is p equals to vt multiply by ia so here substitute the value so vt is 230 multiplied by 60.

01:39 So here, power supplied will come 13 ,800 watt.

01:46 So this is our answer for b part.

01:51 Now let's see c part.

01:54 So here, in this question, we have to find a mechanical power development by the motor.

02:17 So for this, the formula is p -mo.

02:21 Mechanical is equal to power supplied to the armature minus minus power lost in the armature so here we have so here p mechanical is equals to power supplied is 13 ,800 minus power lost we have to find power loss that is ia square multiplied by r .a.

03:01 So substitute the values that is 13 ,800 minus ia is 60 square multiplied by 0 .15.

03:13 So here when we calculated it will come 13 ,800 minus 540 watt.

03:22 So here when we calculated, we get power mechanical is 13 ,200260 watt.

03:22 So here when we calculated, we get power mechanical is 13 ,200 so this is our answer for c part.

03:37 Now let's see d part...

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