A 240 g mass attached to a horizontal spring oscillates at a frequency of 2.80 Hz. At t=0s , the mass is at x = 6.40 cm and has v = -40.0 cm/s.
Added by Mario M.
Step 1
We know that the frequency (f) is related to the mass (m) and the spring constant (k) by the formula: f = 1/(2π) * sqrt(k/m) Rearranging this formula to solve for k, we get: k = (2πf)^2 * m Substituting the given values: k = (2π*2.80 Hz)^2 * 0.240 kg = 20.94 Show more…
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