00:02
Hi, in the given problem, the voltage fed to the power transmission line is 240 k -kilovolt.
00:15
Or we can say this is 240 into 10 -dhast -to -part 3 volt.
00:22
This transmission line is carrying a current i is equal to 5 .00 into 10 -drease to the 2 ampere or simply we can say this is 500 ampere.
00:38
The resistance of ceramic insulator, each ceramic insulator, each insulator is given as 1 .00 into 10 dash to the part 9 oom.
01:04
In the first part of the problem, we have to find the net resistance of 100 such insulator.
01:12
As all these insulators are in series.
01:28
So net resistance of all the insulators in series r s will be given as n times of r means 100 times of resistance of one insulator is 1 .00 into 10 to power 9 o.
01:51
So this net resistance of all the insulators come out to be 100 into 10 to the part 9 om or we can say this is r s is equal to 1 .00 into 10 dash the power 11 om this is the answer for the first part of the problem now in the second part of the problem we have to find the power dissipating by all of these insulators.
02:32
So the power dissipated is given by the expression p is equal to v squared by r s net resistance...