A 2.47 m aqueous solution of Fe(ClO4)3 has a freezing point of -17.81 oC. What is the van't Hoff factor for this solution? Water has a freezing point of 0.00 oC and a Kf = 1.86 oC/m. Group of answer choices none of the answers are correct 2.93 3.82 3.88 4.00
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Step 1
First, we need to find the molality of the solution. We can use the formula: ΔTf = Kf * molality * i where ΔTf is the change in freezing point, Kf is the freezing point depression constant for water, molality is the molality of the solution, and i is the van't Show more…
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