It is:
\[ 2 \mathrm{N}_{2} \mathrm{O}_{3}(\mathrm{~g}) \rightarrow 4 \mathrm{NO}_{2}(\mathrm{~g}) + \mathrm{O}_{2}(\mathrm{~g}) \]
From this equation, we can see that for every 2 moles of \( \mathrm{N}_{2} \mathrm{O}_{3} \), 4 moles of \( \mathrm{NO}_{2} \) and
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