Question

A 25 kg box is sitting on an incline( not moving, the coefficient of static friction of the incline is 0. 1 , initially ?=2.5 degrees, as shown in the diagram ). As Joe Doe starts to tilt the angle of the incline (?) higher, the box starts to slide. After it just starts to slide what will the acceleration be equal to? The coefficient of kinetic friction of the incline is 0.01. Consider g=10m/s^2.

Name: A 25 kg box is sitting on an incline( not moving, the coefficient of static friction of the incline is 0. 1 , initially ?=2.5 degrees, as shown in the diagram ). As Joe Doe starts to tilt the angle of the incline (?) higher, the box starts to slide. After it just starts to slide what will the acceleration be equal to? The coefficient of kinetic friction of the incline is 0.01. Consider g=10m/s^2.
Uploaded: 2022-04-09T12:56:02-08:00
Duration: 2 min 43 s
Channel: Khoobchandra Agrawal
Description: A 25 kg box is sitting on an incline( not moving, the coefficient of static friction of the incline is 0. 1 , initially ?=2.5 degrees, as shown in the diagram ). As Joe Doe starts to tilt the angle of the incline (?) higher, the box starts to slide. After it just starts to slide what will the acceleration be equal to? The coefficient of kinetic friction of the incline is 0.01. Consider g=10m/s^2.

          A 25 kg box is sitting on an incline( not moving, the coefficient of static friction of the incline is 0. 1 , initially ?=2.5 degrees, as shown in the diagram ). As Joe Doe starts to tilt the angle of the incline (?) higher, the box starts to slide. After it just starts to slide what will the acceleration be equal to? The coefficient of kinetic friction of the incline is 0.01. Consider g=10m/s^2.

A 25 kg box is sitting on an incline( not moving, the coefficient of static friction of the incline is 0. 1 , initially ?=2.5 degrees, as shown in the diagram ). As Joe Doe starts to tilt the angle of the incline (?) higher, the box starts to slide. After it just starts to slide what will the acceleration be equal to? The coefficient of kinetic friction of the incline is 0.01. Consider g=10m/s^2.

Added by Sonia W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Khoobchandra Agrawal

04/09/2022

Step 1

W = 25 kg * 10 m/s^2 = 250 N Show more…

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A 25 kg box is sitting on an incline( not moving, the coefficient of static friction of the incline is 0. 1 , initially Θ=2.5 degrees, as shown in the diagram ). As Joe Doe starts to tilt the angle of the incline (Θ) higher, the box starts to slide. After it just starts to slide what will the acceleration be equal to? The coefficient of kinetic friction of the incline is 0.01. Consider g=10m/s^2.