00:01
In this problem, we have been given that there is a 2 .5 kgm mass object.
00:06
And this object is starting from rest, so its initial speed will be 0 meter per second.
00:12
And this object moves through the points a, b, c, d and e, as shown here in the diagram for potential energy versus the distance moved along the x -axis.
00:24
So from this diagram, we need to determine the speed of the object in meter per second, at the points b, c, and d.
00:34
So for this we will use the energy conservation.
00:37
So to determine the speed of the object at point b, we first see that the dropping the potential energy is from 30 joules to 5 joules, and that is by 25 joules.
00:51
And this change in potential energy or the dropping potential energy will be gained by the kinetic energy.
00:59
So the gain in kinetic energy is equal to the loss in potential energy, and that will be half mv square, because initially the object is at rest.
01:07
So from here, if we put the value of m as 2 .5, we're going to get here 25 times 2 divided by 2 .5, and the root of that will be the speed of the object, and that will be 4 .5 meter per second.
01:23
So this is the speed of object at point b.
01:27
Similarly, to get the speed at point c, what we can do here is again use the energy conservation...