Question

A 25 N force is applied to a bar that can pivot around its end as shown below. r ? F The force is 0.77 m away from the end and at an angle $\theta = 60^\circ$. What is the torque on the bar? Do not include any sign (+ or -) in your answer. Doing so will count your answer as wrong.

          A 25 N force is applied to a bar that can pivot around its end as shown below.
r
?
F
The force is 0.77 m away from the end and at an angle $\theta = 60^\circ$. What is the torque on the bar? Do not include any sign (+ or -) in your answer. Doing so will count your answer as wrong.

A 25 N force is applied to a bar that can pivot around its end as shown below.
r
?
F
The force is 0.77 m away from the end and at an angle θ = 60^∘. What is the torque on the bar? Do not include any sign (+ or -) in your answer. Doing so will count your answer as wrong.

Added by James R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Narayan Hari

11/25/2022

Step 1

The torque (τ) on an object is given by the formula: τ = r * F * sin(θ) where r is the distance from the pivot point to the point where the force is applied, F is the magnitude of the force, and θ is the angle between the force vector and the lever arm. Show more…

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A 25 N force is applied to a bar that can pivot around its end as shown below. Ө F The force is 0.77 m away from the end and at an angle 0 = 60°. What is the torque on the bar? Do not include any sign (+ or -) in your answer. Doing so will count your answer as wrong. A 25 N force is applied to a bar that can pivot around its end as shown below. The force is 0.77m away from the end and at an angle =60.What is the torgue on the bar? Do not include any sign(+or- in your answer. Doing so will count your answer as wrong