A 250 g, 21-cm-diameter plastic disk is spun on an axle through its center by an electric motor. Part A: What torque must the motor supply to take the disk from 0 to 1700 rpm in 5.0 s?
Added by Sharon H.
Step 1
The moment of inertia of a disk is given by the formula: I = (1/2)mr^2 where m is the mass of the disk and r is the radius of the disk. In this case, m = 0.25 kg and r = 0.105 m (half of the diameter). Therefore: I = (1/2)(0.25 kg)(0.105 m)^2 = 0.00138 kg·m^2 Show more…
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