'A 25.0 mL sample of 0.100 M NH3 (Kb = 1.8 . 10-5) is titrated with 0.100 M HCI What is the pH at the equivalence point? Report your answer to two decimal places:'
Added by Bradley C.
Step 1
At the equivalence point, the moles of NH3 and HCl are equal. We can calculate the moles of NH3 in the 25.0 mL sample: moles of NH3 = (0.100 mol/L) * (0.025 L) = 0.0025 mol Show more…
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