00:01
Here in this problem given a276 milliliter aqueous solution containing 0 .400 grams of an unknown polymer has an osmotic pressure of 26 .9 torr at 30 degree celsius.
00:13
We have to find out the molar mass of the polymer.
00:16
Let m be the molar mass of the polymer, molar mass of the polymer.
00:30
Now, here the pressure given 26 .9 torr and we will convert to atm 26 .9 torr times the conversion factor 1 atm divided by 760 torr because 1 atm is 760 torr and we get 26 .9 divided by 760 atm.
00:58
Temperature given 30 degree celsius.
01:01
We will convert to kelvin by adding 273 and we get 303 kelvin.
01:09
Now, recall the formula pi osmotic pressure that is equal to crt, c molar concentration, r gas constant, t kelvin temperature.
01:25
Here by given 26 point, not given, we converted 26 .9 divided by 760 atm.
01:34
C molar concentration, that will be number of moles...