Question

A 2.90 μF capacitor is connected to a 12.0 V battery for a long time, and then is disconnected. The capacitor briefly runs a 2.00 W toy motor for 21.0 s. A) After this time, by how much has the energy stored in the capacitor decreased? (in J) B) What is the voltage across the plates? (in V) C) How much charge is stored on the capacitor? (in C) D) How much longer could the capacitor run the motor, assuming the motor ran at full power until the end? (in sec)

Name: a 290 f capacitor is connected to a 120 v battery for a long time and then is disconnected the capacitor briefly runs a 200 w toy motor for 210 s a after this time by how much has the energy 29152
Uploaded: 2022-05-13T14:25:00-08:00
Duration: 2 min 38 s
Channel: Shaiju T
Description: a 290 f capacitor is connected to a 120 v battery for a long time and then is disconnected the capacitor briefly runs a 200 w toy motor for 210 s a after this time by how much has the energy 29152

          A 2.90 μF capacitor is connected to a 12.0 V battery for a long time, and then is disconnected. The capacitor briefly runs a 2.00 W toy motor for 21.0 s.

A) After this time, by how much has the energy stored in the capacitor decreased? (in J)
B) What is the voltage across the plates? (in V)
C) How much charge is stored on the capacitor? (in C)
D) How much longer could the capacitor run the motor, assuming the motor ran at full power until the end? (in sec)

Added by Alex C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Shaiju T

05/13/2022

Step 1

90 μF, V = 12.0 V Using the formula U = 0.5 * C * V^2 U = 0.5 * 2.90 * 10^-6 * (12.0)^2 U = 208.8 J Show more…

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A 2.90 μF capacitor is connected to a 12.0 V battery for a long time, and then is disconnected. The capacitor briefly runs a 2.00 W toy motor for 21.0 s. A) After this time, by how much has the energy stored in the capacitor decreased? (in J) B) What is the voltage across the plates? (in V) C) How much charge is stored on the capacitor? (in C) D) How much longer could the capacitor run the motor, assuming the motor ran at full power until the end? (in sec)