00:01
Hello students, according to part a we are going to find out the excitation voltage by using the formula ef is equals to v phase plus ia into ra plus j xs.
00:21
Here we are going to substitute the values root 3 into 11000 into root 3.
00:31
From this we get excitation potential ef is equals to 11000 volt.
00:41
Next we are going to find out second part of part a stator current during short circuit.
01:06
Here we can consider terminal voltage is equals to zero and stator current is equals to ef divided by ra plus j xs.
01:32
Now we can substitute the values 11000 divided by root 3 divided by 1 .5 plus j 15.
01:46
Here we get to start the current is equals to 421 .2 minus 884 .2 angle ampere stator current.
02:05
Next part b in part b we are going to find out first excitation voltage.
02:20
Excitation voltage ef is equals to 11000 divided by root 3 plus ia angle 36 .8 degree plus 1 .5 plus j 15.
02:53
Now we are going to use rated ammeter current.
03:06
Ia is equals to 2000 into 10 to the power of 3 divided by root 3 into 11 into 10 to the power of 3.
03:20
Here we get ia is equals to 104 .9 ampere...