A $.30-06$ bullet has a mass of 0.010 kg. If the average force on the bullet is $9000 \mathrm{N},$ what is the bullet's average acceleration?
Added by Alfred J.
Step 1
Step 1: Recall the formula for average acceleration: $a = \frac{F}{m}$, where $a$ is the acceleration, $F$ is the force, and $m$ is the mass. Show more…
Show all steps
Your feedback will help us improve your experience
Iksha T and 66 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A 150 -grain $.30-06$ bullet has a mass of $0.01 \mathrm{kg}$ and a muzle velocity of $900 \mathrm{m} / \mathrm{s}$. If it takes $1 \mathrm{ms}$ (millisecond) to travel down the barrel, what is the average force acting on the bullet?
A 23.2-g bullet is fired from a rifle. It takes 2.15 × 10^-3 s for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 690 m/s. Assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet.
Dwijendra R.
A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average force exerted on a 0.0300 -kg bullet to accelerate it to a speed of 600 $\mathrm{m} / \mathrm{s}$ in a time of 2.00 $\mathrm{ms}$ (milliseconds)?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD