A 30 cm thick wall of 5m x 3m size is made of red brick (k = 0.3 W/m °C). It is covered on both sides by layers of plaster, 2 cm thick (k = 0.6 W/m °C). The wall has a window size of 1m x 2m. The window door is made of 12 mm thick glass (k = 1.2 W/m °C). If the inner and outer surface temperatures are 15 °C and 40 °C. Make the calculation for the rate of heat flow through the wall.

Name: A 30 cm thick wall of 5m x 3m size is made of red brick (k = 0.3 W/m °C). It is covered on both sides by layers of plaster, 2 cm thick (k = 0.6 W/m °C). The wall has a window size of 1m x 2m. The window door is made of 12 mm thick glass (k = 1.2 W/m °C). If the inner and outer surface temperatures are 15 °C and 40 °C. Make the calculation for the rate of heat flow through the wall.
Uploaded: 2024-10-14T06:36:11-08:00
Duration: 2 min 25 s
Channel: Anand Jangid
Description: A 30 cm thick wall of 5m x 3m size is made of red brick (k = 0.3 W/m °C). It is covered on both sides by layers of plaster, 2 cm thick (k = 0.6 W/m °C). The wall has a window size of 1m x 2m. The window door is made of 12 mm thick glass (k = 1.2 W/m °C). If the inner and outer surface temperatures are 15 °C and 40 °C. Make the calculation for the rate of heat flow through the wall.

          A 30 cm thick wall of 5m x 3m size is made of red brick (k = 0.3 W/m °C). It is covered on both sides by layers of plaster, 2 cm thick (k = 0.6 W/m °C). The wall has a window size of 1m x 2m. The window door is made of 12 mm thick glass (k = 1.2 W/m °C). If the inner and outer surface temperatures are 15 °C and 40 °C. Make the calculation for the rate of heat flow through the wall.

A 30 cm thick wall of 5m x 3m size is made of red brick (k = 0.3 W/m °C). It is covered on both sides by layers of plaster, 2 cm thick (k = 0.6 W/m °C). The wall has a window size of 1m x 2m. The window door is made of 12 mm thick glass (k = 1.2 W/m °C). If the inner and outer surface temperatures are 15 °C and 40 °C. Make the calculation for the rate of heat flow through the wall.

Added by Mukesh B.

Physics

Robert Coleman Richardson; Betty… 5th Edition

Chapter 14

Instant Answer

Solved by Expert Anand Jangid

10/14/2024

Step 1

The total area of the wall is \(5 \mathrm{~m} \times 3 \mathrm{~m} = 15 \mathrm{~m}^2\). The area of the window is \(1 \mathrm{~m} \times 2 \mathrm{~m} = 2 \mathrm{~m}^2\). So, the effective area of the wall (excluding the window) is \(15 \mathrm{~m}^2 - 2 Show more…

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