00:01
All right, so let's say we have a rectangular door supported by two hinges, one and two.
00:05
The door has a height of 2 .5 meters and a force is applied at a 20 degree angle this way, which is 62 newtons, and this is a distance we'll call y of one meter.
00:22
And the width of the door is, let's see, 1 .22 meters.
00:27
So we want to know what's the force applied by the top hinge.
00:30
So let's pick the bottom hinge as our kind of pivot point.
00:34
What we'll have is the force applied at the top hinge.
00:37
We'll call that like f, guess what, f1 times h, which is the torque that it applies with a negative sign, plus the torque exerted about the other force.
00:51
So fw sine theta, or sorry, the distance is going to be the square root of w squared plus y squared times the sine of theta.
01:04
All right, so let's call it phi because i don't want to use the same variable.
01:07
We'll call it phi...