0:00
Hello everyone.
00:01
So here we are given that we have a 300 gram bullet.
00:05
It is hit on a 3kg block.
00:08
The initial velocity of the bullet is given to be 400 meter per second.
00:12
But the initial velocity of the block is 0 meter per second.
00:16
At the end, when it is hit by the bullet, the bullet buries itself.
00:21
When the bullet buries itself, then the final velocity of the bullet will go zero.
00:26
Hence we have to find the final velocity of the block.
00:31
From the law of conservation of momentum, we know that the initial momentum of the whole system, that is the momentum of the bullet plus the momentum of the block initially is equal to the final momentum of the whole system, that m1 v1 plus m2 v2.
00:51
So this is the law of conservation of momentum.
00:53
Let us start by putting the values.
00:55
300 grams into kgues will be 300 multiplied by 10 raised to the power minus 3.
01:01
U1 is given to be 400 meter per second plus m2 is 3 kg.
01:07
U2 is given to be 0...