A 300-lb block rests on a plane inclined at 36.87° from the horizontal. A 100 lb force pushes this block up the plane. The coefficient of friction between the block and the plane shown is 0.35. If the block is in equilibrium, determine the magnitude of the friction force.
Added by Alvaro C.
Step 1
The normal force is the component of the weight that acts perpendicular to the inclined plane. It can be calculated using the formula: Normal Force = Weight * cos(θ) where θ is the angle of the inclined plane. So, Normal Force = 300 lb * cos(36.87°) = 240 lb Show more…
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