Question

A 33-mm wide diffraction grating produces a deviation 33.0° in the second order principal maxima. The wavelength of light is 606 nm. What is the total number of slits on the grating? Hint: $\sin(\theta) = \frac{m\lambda}{d}$, ($m = 0, 1, 2, ...$) (diffraction grating, principal maxima) m: the order of the pattern, d: width of each slit, and $\lambda$: the wavelength of the light. 1 nm = $10^{-9}$ m and 1 mm = $10^{-3}$ m.

          A 33-mm wide diffraction grating produces a deviation 33.0° in the second order principal maxima. The wavelength of light is 606 nm. What is the total number of slits on the grating?
Hint: $\sin(\theta) = \frac{m\lambda}{d}$, ($m = 0, 1, 2, ...$) (diffraction grating, principal maxima)
m: the order of the pattern, d: width of each slit, and $\lambda$: the wavelength of the light.
1 nm = $10^{-9}$ m and 1 mm = $10^{-3}$ m.

$A 33-mm wide diffraction grating produces a deviation 33.0° in the second order principal maxima. The wavelength of light is 606 nm. What is the total number of slits on the grating? Hint: sin(θ) = (mλ)/(d), (m = 0, 1, 2, ...) (diffraction grating, principal maxima) m: the order of the pattern, d: width of each slit, and λ: the wavelength of the light. 1 nm = 10^-9 m and 1 mm = 10^-3 m.$

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