00:01
High students in this question, it is given that aluminum is been kept inside water and a few data related to this question is given below which include mass of aluminum which can be taken as ma and the magnitude of ma is taken to be 3 .5 kilograms.
00:17
On the other hand, mass of water can be taken as mb which is equal to 1 kilogram.
00:22
Now the initial temperature of aluminum can be taken as ca which is equal to 29 .5 degrees celsius.
00:30
On the other hand, initial temperature of water is taken as cb which is equal to 20 degrees celsius.
00:36
Now the specific heat of aluminum is taken as ca which is equal to 900 jude per kilogram degree celsius.
00:45
On the other hand, specific heat of water is taken as cb which is equal to 4 ,186 jude per kilogram degree celsius.
00:54
Now the final temperature in this case can be taken as tf and the value of this tf can be found out by applying the law of conservation of heat energy.
01:03
According to which we can write that, the product of m -a into c -a into t -a -m -a -m -a -minus t -f will be equal to the product of m -b into c -b into t -f -m -b.
01:18
Now here by rearranging this equation, we get the equation of final temperature t -f -2.
01:24
Equal to m .a .c .a.
01:28
Into ta plus a value of mb cb into tb, the whole divided by ma into ca plus mb into cb...