Question

6. A 4.0-kg block is put on top of a 5.0-kg block. To cause the top block to slip on the bottom one, which is held fixed, a horizontal force of at least 12 N must be applied to the top block. The assembly of blocks is now placed on a horizontal frictionless table. Find (a) the magnitude of the maximum horizontal force F that can be applied to the lower block so that the blocks will move together and (b) the resulting acceleration of the blocks.

Name: 6. A 4.0-kg block is put on top of a 5.0-kg block. To cause the top block to slip on the bottom one, which is held fixed, a horizontal force of at least 12 N must be applied to the top block. The assembly of blocks is now placed on a horizontal frictionless table. Find (a) the magnitude of the maximum horizontal force F that can be applied to the lower block so that the blocks will move together and (b) the resulting acceleration of the blocks.
Uploaded: 2022-07-14T07:55:23-08:00
Duration: 2 min 10 s
Channel: Prabhu Ramji

          6. A 4.0-kg block is put on top of a 5.0-kg block. To cause the top block to slip on the bottom one, which is held fixed, a horizontal force of at least 12 N must be applied to the top block. The assembly of blocks is now placed on a horizontal frictionless table. Find (a) the magnitude of the maximum horizontal force F that can be applied to the lower block so that the blocks will move together and (b) the resulting acceleration of the blocks.

6. A 4.0-kg block is put on top of a 5.0-kg block. To cause the top block to slip on the bottom one, which is held fixed, a horizontal force of at least 12 N must be applied to the top block. The assembly of blocks is now placed on a horizontal frictionless table. Find (a) the magnitude of the maximum horizontal force F that can be applied to the lower block so that the blocks will move together and (b) the resulting acceleration of the blocks.

Added by Roberto D.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

07/14/2022

Step 1

This force is applied to the top block, which has a mass of 4.0 kg. Therefore, the maximum acceleration of the top block is given by a = F/m = 12 N / 4.0 kg = 3.0 m/s^2. Show more…

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A 4.0-kg block is put on top of a 5.0-kg block. To cause the top block to slip on the bottom one, which is held fixed, a horizontal force of at least 12 N must be applied to the top block. The assembly of blocks is now placed on a horizontal frictionless table. Find (a) the magnitude of the maximum horizontal force F that can be applied to the lower block so that the blocks will move together and (b) the resulting acceleration of the blocks. (HRW10e 6.61; see also 29)