A 4.00-kg block rests on a 30.0 degree incline as shown in Fig. 5-5. If the coefficient of static friction between the block and the incline is 0.700, with what magnitude force must a horizontal force act on the block to start it moving up the incline?
Added by Collin G.
Step 1
The component parallel to the incline is \(mg \sin(\theta)\) and the component perpendicular to the incline is \(mg \cos(\theta)\), where \(m = 4.00 \, \text{kg}\), \(g = 9.8 \, \text{m/s}^2\), and \(\theta = 30.0^\circ\). Show more…
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