A 4.00-m-long pole stands vertically in a freshwater lake having a depth of 2.80 m. The Sun is 37.5° above the horizontal. Determine the length of the pole's shadow on the bottom of the lake.
Added by Gregory R.
Step 1
- Sun is 37.5° above the horizontal, so with respect to the vertical (the normal to the water surface) the incidence angle in air is 90° − 37.5° = 52.5°. - Use Snell’s law: n_air sin(θ1) = n_water sin(θ2). n_air ≈ 1.00, n_water ≈ 1.333. sin(θ2) = Show more…
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A 4.00-m-long pole stands vertically in a freshwater lake having a depth of $2.00 \mathrm{m}$. The Sun is $40.0^{\circ}$ above the horizontal. Determine the length of the pole's shadow on the bottom of the lake.
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A 4.00-m-long pole stands vertically in a lake. The depth of the lake is 2.00 m. The sun is 40° above the horizontal. Determine the length of the pole's shadow on the bottom of the lake.
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