A 4.00-m-long pole stands vertically in a lake having a depth of 2.00 m. When the Sun is 40.0 degrees above the horizontal, determine the length of the pole's shadow on the bottom of the lake. Take the index of refraction for water to be 1.33.
Added by Dorothy R.
Step 1
00$ m, $d = 2.00$ m, $\theta = 40.0^\circ$ $s_1 = 4.00 - 2.00\tan(40.0^\circ)$ $s_1 \approx 2.42$ m ** Show more…
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A (0. A $4.00$ -m-long pole stands vertically in a lake having a depth of $2.00 \mathrm{~m}$. When the Sun is $40.0^{\circ}$ above the horizontal, determine the length of the pole's shadow on the bottom of the lake. Take the index of refraction for water to be $1.33$.
A 4.00-m-long pole stands vertically in a freshwater lake having a depth of $2.00 \mathrm{m}$. The Sun is $40.0^{\circ}$ above the horizontal. Determine the length of the pole's shadow on the bottom of the lake.
A 4.00-m-long pole stands vertically in a freshwater lake having a depth of 2.15 m. The Sun is 37.0° above the horizontal. Determine the length of the pole's shadow on the bottom of the lake.
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