00:01
Hi, here in this given problem, length of the string, length of the wire, whatever we can say.
00:14
This is given to be equal to 41 centimeter or that is 0 .41 meter.
00:23
It's mass, m, that is 7 .7 gram.
00:34
Or we can say 7 .7 into 10 to the power minus 3 kilogram.
00:41
T created in it 200 newton so for the fundamental frequency created in this wire if it is stretched between two ends in the fundamental mode of vibration it will be vibrating only in a single loop single loop means half of the wavelength and this is l so length of the wire that is equal to lambda y2 so lambda will be equal to twice of l.
01:27
So using an expression for the speed of the wave created over the string, v is equal to f into lambda.
01:36
So the frequency will be given by v by lambda for lambda to l.
01:43
And v, speed of transverse wave is given as square root of tension t divided by mu...