00:01
Hello students, in this question we have to find out the mass percentage of chlorine in sample which was titrated against silver nitrate solution.
00:10
The number of moles of silver nitrate given to us would be equal to its given mass divided by its molecular weight.
00:18
The given mass is 4 .3 grams and its molecular weight is 169 .87 grams per mole.
00:29
The number of moles come out to be 0 .025 mole.
00:37
The molarity of a solution is equal to the number of moles of solute present in 1 liter of the solution.
00:52
The molarity of silver nitrate would be equal to the number of moles of silver nitrate which are 0 .025 divided by the volume of solution which is 250 milliliters.
01:07
To convert it into liters we will use the relation that there are 1000 milliliters in 1 liter.
01:14
The molarity of silver nitrate comes out to 0 .1 molar.
01:22
The volume of this solution required for titration is equal to 20 milliliters.
01:31
There are 0 .1 mole of silver ions in 1 liter of the solution.
01:44
In 20 milliliters of the solution the moles of silver would be equal to 0 .1 divided by 1000 milliliter multiplied by 20 milliliter...